Reshape Matrix array manipulations

Problem statement

In MATLAB, there is a very useful function called 'reshape', which can reshape a matrix into a new one with different size but keep its original data.

You're given a matrix represented by a two-dimensional array, and two positive integers r and c representing the row number and column number of the wanted reshaped matrix, respectively.

The reshaped matrix need to be filled with all the elements of the original matrix in the same row-traversing order as they were.

If the 'reshape' operation with given parameters is possible and legal, output the new reshaped matrix; Otherwise, output the original matrix.

Link to GitHub : Code

Example 1:

Input: 
nums = 
[[1,2],
 [3,4]]
r = 1, c = 4
Output: 
[[1,2,3,4]]
Explanation:
The row-traversing of nums is [1,2,3,4]. The new reshaped matrix is a 1 * 4 matrix, fill it row by row by using the previous list.

Example 2:

Input: 
nums = 
[[1,2],
 [3,4]]
r = 2, c = 4
Output: 
[[1,2],
 [3,4]]
Explanation:
There is no way to reshape a 2 * 2 matrix to a 2 * 4 matrix. So output the original matrix.

Solution

• We cannot reshape array 2* 2 to 2* 4  matrix. If this is the situation we need to return the array
• We need to declare new matrix array 

             int [][] reshapedArray= new int [r][c]

• The reshape matrix would be defined using 

           reshapedArray[i/c][i%c]=nums[i/firstArrayLength][i%firstArrayLength]

package Algorithms;

public class ReshapeArray {
 
 public static int [][] get(int [][] nums,int r, int c){
  
  int arrayNums=nums.length;
  int firstArrayLength=nums[0].length;
  
  //We cannot reshape an array of 2 * 2 matrix to a 2 * 4 matrix
  if(arrayNums*firstArrayLength!=r*c )
   return nums;
   else
   {
    //New reshaped array
    int [][] reshapedArray= new int [r][c];
    for (int i=0;i<r*c;i++)
    {
                 1st iteration
  new[0/4][0%4]=nums[0/2][0%2];
  new[0][0]=nums[0][0]
      
  2nd iteration
  new[1/4][1%4]=nums[1/2,1%2]
  new[0][1]    =nums[0][1]
      
  3rd iteration
  new[2/4][2%4]=nums[2/2,2%2]
  new[0][2] = nums[1,0]
      
  4th iteration
  [3/4][3%4]=nums[3/2,3%2]
  new[0][3] =nums[1,1]
                     */
     reshapedArray[i/c][i%c]=nums[i/firstArrayLength][i%firstArrayLength];
    }
        return reshapedArray;
   }
    
  
 }

}

Iteration