Problem Statement
Given a binary array, find the maximum number of consecutive 1s in this array.Link to GitHub :Code
Example 1:
Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.
Note:
- The input array will only contain
0
and1
. - The length of input array is a positive integer and will not exceed 10,000
110111
^ maxHere = 1
110111
.^ maxHere = 2
110111
..^ maxHere = 0
110111
...^ maxHere = 1
110111
....^ maxHere = 2
110111
.....^ maxHere = 3
public class MaxConsecutiveOnes { public static int get(int [] arr) { int maxNow=0,max=0; //loop through the array to find the maximum no of consecutive arrays for( int i :arr) { //Reset MaxNow to 0 or else increment by one max=Math.max(max,maxNow= i==0 ?0 :maxNow+1) ; } return max; } }
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