Problem Statement
Given a string s consists of upper/lower-case alphabets and empty space characters' '
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
Link to GitHub : CodeGiven s = "Prathap Kudupu", return 6.
Solution
- The result is the difference between the length of the string and and index of empty space
public static int optimum(String s) { return s.trim().length()-s.trim().indexOf(' ')-1; }
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